2y^2-4y-8x-20=0

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Solution for 2y^2-4y-8x-20=0 equation:


Simplifying
2y2 + -4y + -8x + -20 = 0

Reorder the terms:
-20 + -8x + -4y + 2y2 = 0

Solving
-20 + -8x + -4y + 2y2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '20' to each side of the equation.
-20 + -8x + -4y + 20 + 2y2 = 0 + 20

Reorder the terms:
-20 + 20 + -8x + -4y + 2y2 = 0 + 20

Combine like terms: -20 + 20 = 0
0 + -8x + -4y + 2y2 = 0 + 20
-8x + -4y + 2y2 = 0 + 20

Combine like terms: 0 + 20 = 20
-8x + -4y + 2y2 = 20

Add '4y' to each side of the equation.
-8x + -4y + 4y + 2y2 = 20 + 4y

Combine like terms: -4y + 4y = 0
-8x + 0 + 2y2 = 20 + 4y
-8x + 2y2 = 20 + 4y

Add '-2y2' to each side of the equation.
-8x + 2y2 + -2y2 = 20 + 4y + -2y2

Combine like terms: 2y2 + -2y2 = 0
-8x + 0 = 20 + 4y + -2y2
-8x = 20 + 4y + -2y2

Divide each side by '-8'.
x = -2.5 + -0.5y + 0.25y2

Simplifying
x = -2.5 + -0.5y + 0.25y2

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